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- for a change AND (SELECT 4339 FROM(SELECT COUNT(*),CONCAT(0x7170717871,(SELECT (ELT(4339=4339,1))),0x716b707a71,FLOOR(RAND(0)*2)
- For an exam with a mean of M = 74 and a standard deviation of s = 8, Mary has a score of X = 80, Bob’s score corresponds to z =
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- For any scalar p prove that: = = − − − 2 3 2 3 2 3 x x 1 px y y 1 py (1 pxyz)(x y)(y z)(z x) z z 1 pz
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